4=(x^2)^2+3x^2

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Solution for 4=(x^2)^2+3x^2 equation: 



4=(x^2)^2+3x^2

We move all terms to the left:

4-((x^2)^2+3x^2)=0

We get rid of parentheses

-x^2^2-3x^2+4=0

We add all the numbers together, and all the variables

-3x^2-x^2^2+4=0

We move all terms containing x to the left, all other terms to the right

-3x^2-x^2^2=-4

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